1x^2-25x+136=0

Solution for 1x^2-25x+136=0 equation:

1x^2-25x+136=0

We add all the numbers together, and all the variables

x^2-25x+136=0

a = 1; b = -25; c = +136;
Δ = b2-4ac
Δ = -252-4·1·136
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-9}{2*1}=\frac{16}{2}
=8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+9}{2*1}=\frac{34}{2}
=17
$